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Combinatorics · Last catalog review 26 Jul 2026

Erdős Problem 236

Let f(n)f(n) count the number of solutions to n=p+2kn=p+2^k for prime pp and k0k\geq 0. Show that f(n)=o(logn)f(n)=o(\log n).
Published 6 May 2026Never attempted

Formal statement

Lean type

(fun n => ↑(Erdos236.f n)) =o[Filter.atTop] fun n => Real.log ↑n

What you must prove

import FormalConjectures.ErdosProblems.«236»
import TaskSupport

namespace Bounty

theorem target : fcTypeOfName% "Erdos236.erdos_236" := by
  sorry

end Bounty

Pinned source: FormalConjectures/ErdosProblems/236.lean

Source type SHA-256
sha256:b364b1aa2fb7181e7c8139c6133d3eb644e83ab723524c0f8dbe8d5de7fd430a
Task id
fc-e923379e-erdos236-erdos-236-bb09909b42-formalized-v1
Task commitment
sha256:79f1a483309394a7a38b2a012c19f3563503901fd7dc0ce89ed92425f97c21e1

Something wrong with this formalization?

A statement that does not faithfully capture the original conjecture is the one real risk here, so we would rather hear about it early — before someone spends weeks on it.

Erdős Problem 236 · Conjectures.io